ABCD is a rhombus. If angle DAC = 50°, find angle ACD, CAB and ABC
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Given : ABCD is a rhombus.
angle DAC=50,
To find : (a)angle ACD (b) angle CAB (c)angle ABC.
Solution:
∠DAC = 50°
ABCD is a rhombus. => AB = BC = CD = AD
rhombus is a parallogram also
hence AB || CD and BC || AD
in ΔACD AD = CD
Hence ∠ACD = ∠DAC
=> ∠ACD = 50°
AB || DC
∠CAB = ∠ACD ( interior alternate angles)
=> ∠CAB = 50°
in ΔABC
AB = BC Hence ∠ACB = ∠CAB = 50°
∠ACB + ∠CAB + ∠ABC = 180°
=> 50° + 50° + ∠ABC = 180°
=> ∠ABC = 80°
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