Question

ABCD is a Rhombus in which AB= 10 cm and AC= 16 find :
(1) Area of ABC
(2) Area of rhombus ABCD​

Answer 1

Side of Rhombus are  equal.

AB = BC = CD = DA

∴AC=4×(side)2−(DiagonalBD)2

AC=4×(10)2−(16)2

=400−256

=144

=12cm

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Answer 2

Answer:

Area Of ABCD = Area Of ABC + Area Of ADC

Let A=10cm, B=10cm , C=16cm

S= (10+10+16)/2

= 18cm

Area Of ABC = ROOT {s(s-a)(s-b)(s-c)}

= ROOT { 18(18-10)(18-10)(18-16) }

= ROOT (18*8*8*2)

= ROOT (2*3*3*2*2*2*2*2*2*2)

= 2*2*2*2*3

=48 cm2

Area Of ADC = Area Of ABC ( AC Divides ABCD Into Two Equal Parts )

= 48cm2

Area Of ABCD = (48+48) cm2

= 96 cm2

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