ABCD is a rhombus in which \_ABC= 58° find the measure of \_ ACD
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We are given, ABCD is a rhombus.
so, ∠B = ∠D and ∠A = ∠C .....................................(1)
But, ∠A + ∠B + ∠C + ∠D = 360°
we are given ∠B = ∠D =58° ..................................(2)
so ∠C + ∠C + 116° = 360° [By (1) & (2)]
2∠C = 360° -116°
2∠C = 244°
so, ∠C = 122°
so ∠ACD = ∠C = 122°
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so, ∠B = ∠D and ∠A = ∠C .....................................(1)
But, ∠A + ∠B + ∠C + ∠D = 360°
we are given ∠B = ∠D =58° ..................................(2)
so ∠C + ∠C + 116° = 360° [By (1) & (2)]
2∠C = 360° -116°
2∠C = 244°
so, ∠C = 122°
so ∠ACD = ∠C = 122°
plz mark as brainliest....
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