ABCD is a rhombus in which AC=6cm BD=8cm.Find the side of the rhombus
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Let the point of intersection of AC and BD be O
Now diagonals of rhombus bisect each other at right angles
In triangleAOB rt angled at O
AO=3cmBO=8cm
AO^2+BO^2=AB^2(PYTHAGORUS THM)
3^2+4^2=AB^2
9+16
25=AB^2
AB=(5^2)^1/2
AB=5
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