ABCD is a rhombus in which AC and BD are diagonals intersecting at O. if angle OAB =55 find angle CDO
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Answered by
5
35°
we know that
OAB is intersected into two parts
Hence, DAB will be 55° × 2 = 110°
- Let's assume that CDO = x
According to the question,
DAB + CDA = 180° ( adjacent angles are equal to 180° )
2x + 110° = 180°
x = 35° ans.
Answered by
4
Answer:
x=35° is right answer
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