Math, asked by ansita1207, 7 months ago

ABCD is a rhombus in which AC and BD are diagonals intersecting at O. if angle OAB =55 find angle CDO


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Answered by Anonymous
5

35°

we know that

\bf \angle OAB is intersected into two parts

Hence, \bf \angle DAB will be 55° × 2 = 110°

  • Let's assume that \bf \angle CDO = x

According to the question,

\bf \angleDAB + \bf \angle CDA = 180° ( adjacent angles are equal to 180° )

\bf \to 2x + 110° = 180°

\bf \to x = 35° ans.

Answered by Anonymous
4

Answer:

x=35° is right answer

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