Question

ABCD is a rhombus in which altitude from D on side AB bisects AB. If D-(20xk)° then find value of k​

Answer 1

Answer:

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Answer 2

Answer:

ABCDisarhombus.DO⊥ABatO.AO=BO.

To find out−

T the angles of other rhombus.

Solution−

InΔADO&ΔBDOwehavethesides

AO=BO(given),OD common.

∠AOD=BOD=90  O

(DO⊥AB)

∴ΔADO&ΔBDOare congruent.

⟹AD=DB

But AD=AB(side so fa rhombus0

∴AD=AB=DB

SoΔADB is an equiangular one.

∴∠A=60  

o

=∠C(opposite angle so fa rhombus)

∴∠A+∠C=2×60  o

=120  o

(i)

Now ∠A+∠C+∠B+∠D=360  o

(sum of the angles of a quadrilateral)

⟹∠B+∠D=360  o

−120  o

=240  o

(from i)

⟹∠B=∠D=  2

240  o

 =120  o

(opposite angles of a rhombus)

Ans−∠A=60  o

,∠C=60  o

,∠B=120  o

,∠D=120  

Step-by-step explanation: