ABCD is a rhombus in which altitude from D to sides DM. bisect AB. find the angle of the rhombus
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Answer:
In rhombus the opposite angles are equal.
Then, the answer is:-
angleA = angleC =60°
angleB = angleC =120°
Step-by-step explanation:
At first, See the picture which I have drawn in this answer.
Let,
Every side of the rhombus = a cm
Here we got the information that there is an altitude from D which bisect AB in M point.
That means,
AM is equal to BM
which means that AM = BM = (a/2) cm
Now we can see that,
triangle AMD is a right angled traingle
Now, if we use trigonometry —
Cos A= AM/AD
or, Cos A= a/(a/2)
or, Cos A=1/2
or, Cos A= Cos 60°
or, A= 60°
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