ABCD is a rhombus in which angle ABC =58° Find angle ACD
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Answered by
3
in triangle ABC
angles are supplementary
therefore
58+x+x=180
as AB=BC sides of rhombus
2x=180-58
x=61
angles are supplementary
therefore
58+x+x=180
as AB=BC sides of rhombus
2x=180-58
x=61
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Answered by
2
ACD+ABC+CBA=180
2x+58=180
2x=180-58
x=132÷2
x=61
2x+58=180
2x=180-58
x=132÷2
x=61
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