ABCD is a rhombus in which angle ABC=58° find the measure of angle ACD
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Answered by
43
Here is your solution
We know that :-
Consecutive angles of a rhombus are supplementary.
∠BCD = 180° - ∠ABC
∠BCD= 180° - 58°
∠BCD= 122°
Diagonals of a rhombus bisect the interior angles. (properties of rhombus )
∠ACD = ∠BCD/2
∠ACD= 122°/2
∠ACD= 61°
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Answered by
9
Consecutive angles of a rhombus are supplementary.
∠BCD
= 180° - ∠ABC
= 180° - 58°
= 122°
Diagonals of a rhombus bisect the interior angles.
∠ACD
= ∠BCD/2
= 122°/2
= 61°
∠BCD
= 180° - ∠ABC
= 180° - 58°
= 122°
Diagonals of a rhombus bisect the interior angles.
∠ACD
= ∠BCD/2
= 122°/2
= 61°
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