Question

ABCD is a rhombus in which AO = 4cm and OB = 3 cm. What is the length of the side of the
rhombus?​

Answer 1

In triangle ABO,by Pythagoras theorem

${ab }^{2} = {ao}^{2} + {ob}^{2}$

=4^2+3^2

=16+9

=25

ab=√25=5cm

all sides are of 5cm

as sides of rhombus are equal

.....

Answer 2

Answer:

the length of the side is 5cm

Step-by-step explanation:

ABCD is rhombus,

O is the midpoint,

In ABCD,AO=4cm,OB=3cm

In triangle,AOB=90 degree

By pythagoras theorem

(AB)^2=(AO)^2 +(OB)^2

(AB)^2=(4)^2+(3)^2

(AB)^2=16+9

(AB)^2=25

AB=root 25

AB=5cm