Question

ABCD is a rhombus in which BC=25cm and AD=24cm find sum of diagonals

Answer 1

Diagonals of a rhombus are perpendicular to each other.

In triangle AOB, we have:
AO = 24 cm
AB = 25 cm

So, by Pythagoras theorem, we have:
BO = square root [(25) - (24) ] = 7 cm

Also, the diagonals of a rhombus bisect each other.

So, AC = 2AO = 48 cm
and BD = 2BO = 14 cm

Thus, sum of lengths of diagonals = 48 cm + 14 cm = 62 cm

Answer 2

Answer:

sum of diagonals will be 62 cm and we have to use pythagoras theorem in this question...