Question

Abcd is a rhombus in which DO=3x and AO=4x find tje perimeter of rhombus

Answer 1

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Answer 2

The perimeter of rhombus is 20x.    

Step-by-step explanation:

Given : ABCD is a rhombus with AO =4x and DO = 3x.

We know that diagonals of a rhombus are perpendicular to each other

⇒∠AOD = 90°

Now in right angled ∆AOD

$AD^2 = AO^2 + OD^2$     (Pythagoras theorem)

$AD^2 = (4x)^2 + (3x)^2$

$AD^2 = 16x2 + 9x^2$

$AD^2 = 25x^2$

$AD=\sqrt{25x^2}$

$AD=5x$

Here perimeter of given rhombus =$4 \times (side) = 4 \times AD$

=$4\times AD$

=$4\times 5x$

=20x.