Question

ABCD is a rhombus in which its diagonals AC & BD intersect at point O,where AC=24cm & BD=10 cm.Find its perimeter.

Answer 1

Answer:

52cm

Step-by-step explanation:

Diagonals of a rhombus bisect each other at right angles.

so, AO = 12cm and BO = 5cm

In triangle AOB,

By Pythagoras theorem -

AB^2 = AO^2 + BO^2

=> AB^2 = 12^2 + 5^2

=> AB = √169 = 13cm

As all sides of a rhombus are equal, Perimeter = 4 × AB = 4 × 13 = 52cm