Question

ABCD is a rhombus of side 20 cm if PC is equals to 32 cm and AP is perpendicular to CD find its area

Answer 1

Answer:

The area of the rhombus is

Given:

One side of a rhombus = 20cm and one diagonal = 24 cm

To Find:

The area of a rhombus

Solution:

In the rhombus ABCD,  

Let, AB = 20 cm  

And AC = 24 cm

From the diagram,

AO + CO = 24 cm  

AO = 12 cm  [∵ AO = CO]      

In  

AB = 20 cm and AO= 12 cm

Using Pythagoras Theorem,

Hence, BO = DO = 16 cm

∴ BD = 16 cm + 16 cm = 32 cm.

Answer 2

Answer:

here is your ans 320cm^2

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