Abcd is a rhombus prove that 4 a b square equal to ac square + bd
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in a rhombus abcd
all side are equal (ab=bc=CD=ad)
diagonal bisect at 90'
ao=oc=ac/2
and bo=od=bd/2
in a right angle triangle aob
by Pythagoras theorem
ab²=ao²+ob²
ab²=(ac/2)²+(bd/2)²
by rearranging this equation we get
4ab²=ac²+bd² hence proved
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