Question

Abcd is a rhombus prove that 4 a b square equal to ac square + bd

Answer 1

I hope it help you

in a rhombus abcd

all side are equal (ab=bc=CD=ad)

diagonal bisect at 90'

ao=oc=ac/2

and bo=od=bd/2

in a right angle triangle aob

by Pythagoras theorem

ab²=ao²+ob²

ab²=(ac/2)²+(bd/2)²

by rearranging this equation we get

4ab²=ac²+bd² hence proved

Mark me as brainliest answer