Question

ABCD is a rhombus .prove that AB^2 +BC^2 +CD^2 +DC^2 = AC^2+DB^2

Answer 1

hey dear,


good morning,


refer to given attachment please.

Answer 2

AC Nd dB r diagnols
let's take RHS
by Pythagoras theorem
${ac }^{2} = {ab}^{2} + {bc}^{2}$
${db}^{2} = {bc}^{2} + {cd}^{2}$
hence ur answer is
ac^2+db^2= ab^2+bc^2+dc^2(bc^2=dc^2)+cd^2
hence proved
hope it helps u. : )