ABCD is a rhombus. Show that AC bisects angle A as well as angle c and bd bisects angle b as well as angle d
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rhombusallsideareequalanddiagonolsaredifferentbutintersectat90
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⇒AB=BC=CD=DA
⇒AC⊥BD
InΔABC
⇒AB=BC
⇒∴∠CAB=∠ACB
⇒AO=OC
∴∠ABO=∠CBO
andsimillarlyinΔADC
⇒AD=DC
⇒AO=OC
∴correspondingangleareequal
⇒∠DAC=∠DCA
and∠CDO=∠ADO
Hence,ACbisect∠Aand∠CandBDbisects∠Band∠D
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