Question

ABCD is a rhombus show that diagnol AC biscets LA as well as LC and diagnol BD biscets LB as well as LD

Answer 1

Step-by-step explanation:

Given : ABCD is a rhombus,

i.e., AB = BC = CD = DA.

Similarly, ∠ADB = ∠CDB and ∠ABD = ∠CBD.

Hence, diagonal AC bisects ∠A as well as ∠C and diagonal BD bisects ∠B as well as ∠D.