Question

ABCD is a rhombus. Show that diagnol AC bisects <A as well as <C and diagonal BD bisects <B as well as <D.​

Answer 1

Step-by-step explanation:

I had this same question for my maths exam lol

Answer 2

Answer:

[Inrhombusallsideareequalanddiagonolsaredifferentbutintersectat90degree ]

⇒AB=BC=CD=DA⇒

AC⊥BD

In ΔABC

⇒ AB= BC⇒

∴∠CAB=∠ACB

⇒AO=OC

∴∠ABO=∠CBO and

simillarlyinΔADC

⇒AD=DC

⇒AO=OC

∴corresponding angle are equal

⇒∠DAC=∠DCA

and∠CDO=∠ADO

Hence,AC bisect ∠A and∠C

andBD bisects ∠Band∠D