Question

ABCD is a rhombus. Show that diagonal AC bisects /_A as well as /_C and diagonal BD bisects /_B as well as /_D

Answer 1

Hlew,

Here's your answer...

ABCD is a rhombus

so, it's all side are equal.

Take a triangle ABC

in which AB=AC

AngleACB=AngleBAC. Equation 1

In triangle ADC

AD=CD

so, angle DCA=Angle DAC. Equation2

from 1 and 2

we get,

AC bisect angle A and angle B

similarly,

BD bisect angle C and angle D

Thanks,

Sorry baby 'wink'