ABCD is a rhombus. show that diagonal bisects <Aas well as <c and diagonal BD bisects<Bas well as <D
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Given : ABCD is a rhombus, i.e., AB = BC = CD = DA. Similarly, ∠ADB = ∠CDB and ∠ABD = ∠CBD. Hence, diagonal AC bisects ∠A as well as ∠C and diagonal BD bisects ∠B as well as ∠D
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