ABCD is a rhombus show that the diagonal AC bisects angle A as well as C
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Answer:
in triangle ABC and triangle ADC
AB=CD (given)
AC=AC ( common)
AD=BC (common)
then triangle ABC congruent with triangle ADC
according to c.p.c.t
angle BAC= angle DAC
angle BCA=angle DCA
therefore diagonal AC bisects angle A as well as angle C
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