ABCD is a rhombus such that ∠ ACB =30°. Then ∠ADB is
A) 40°
B) 45°
C) 60°
D) 50
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ABCD is a rhombus such that ∠ ACB =30°. Then ∠ADB is
A) 40°
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Answer: in rhombus ABCD,
angle ACB = angle CAD = 40. (. alt int. angle )
now,
angle AOD = 90 ( diagonal of rhombus bisect each other at 90 degree)
so, in triangle AOD ,
angle COD + angle AOD +angle ODA = 180
40 + 90 + ADB = 180
ADB = 180 - 130= 50
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