ABCD is a rhombus such that ∠ACB = 40º. Then ∠ADB is
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6
Answer:
50 degree
Step-by-step explanation:
∠COB=90o
In △COB
∠COB+∠OBC+∠OBC=180o
∠OBC=180o−90o−40o
∠OBC=50o
∠OBC=∠ADB ....[AD || BC]
∠ADB=50o
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