Question

Abcd is a rhombus such that acb = 40o. Then adb is

Answer 1

angle ADB= angle ABD
= 50°

Answer 2

Given :- ABCD is a rhombus
ACD = 40 degree

to find ADB
SOLUTION:-

ACB = CAD = 50 ( ALTTERNATE INTERIOR ANGLE)

AOD = 90 ( DIAGONALS OF RHOMBUS ARE PERPENDICULAR)

IN TRIANGLE AOD

A + 0 + D = 180 ( ASP OF TRIANGLE)

50 + 90 + D = 180

D = 180- 140

ADB = 40 DEGREE

HOPE IT HELPS YOU!!