Question

ABCD is a rhombus such that ∠ACB = 50°. Then, ∠ADB = ?

Answer 1

Answer:

40 degrees

Step-by-step explanation:

if it's given that angle ACB is 50 degrees then angle DAC is also equal to 50 degrees by alternate interior angles

then if we consider the triangle with angle AOB , ADO and DAC

here O is on the diagonal

as we know that rhombus diagonal are perpendicular bisectors therefore Angle AOB is 90 degrees

so by angle sum property of triangle all the angles should be 180 degrees

AOB + ADO + DAC=180

90+ADO +50 =180

140+ADO= 180

ADO= 180-140

=40 degrees

hence angle ADB is 40 degrees