Math, asked by reenadevharsh221307, 7 months ago

ABCD is a rhombus such that ∟ADB = 50°, then what is the measure of ∟ACB?​

Answers

Answered by bhoomikasanjeev2009
5

Answer:

The diagonals of a rhombus are at right angle to each other .

∴ ∠AOD = 90°

Now , in △AOD , we have

∠ADO + ∠DAO + ∠AOD = 180°

⇒ ∠ADO + 50° + 90° = 180°

⇒ ∠ADO + 140° = 180°

⇒ ∠ADO or ∠ADB = 40°

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