ABCD is a rhombus such that ∟ADB = 50°, then what is the measure of ∟ACB?
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The diagonals of a rhombus are at right angle to each other .
∴ ∠AOD = 90°
Now , in △AOD , we have
∠ADO + ∠DAO + ∠AOD = 180°
⇒ ∠ADO + 50° + 90° = 180°
⇒ ∠ADO + 140° = 180°
⇒ ∠ADO or ∠ADB = 40°
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