ABCD is a rhombus such that angle abc is equals to 40 degree the angle ADC is equal to
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Since <ACB = 40 deg, <BCD = 2*<ACB = 80 deg. <ADC = 180-<BCD = 180–80 = 100 deg, so <ADB = 100/2 = 50 deg.
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Answer: Since <ACB = 40 deg, <BCD = 2*<ACB = 80 deg. <ADC = 180-<BCD = 180–80 = 100 deg, so <ADB = 100/2 = 50 deg.
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