Math, asked by tarikebhure76906, 7 months ago

ABCD is a rhombus such that angle abc is equals to 40 degree the angle ADC is equal to​

Answers

Answered by BhawyaMishra
12

Answer:

Since <ACB = 40 deg, <BCD = 2*<ACB = 80 deg. <ADC = 180-<BCD = 180–80 = 100 deg, so <ADB = 100/2 = 50 deg.

Answered by dhanalakshmivp50
1

Answer:

Answer: Since <ACB = 40 deg, <BCD = 2*<ACB = 80 deg. <ADC = 180-<BCD = 180–80 = 100 deg, so <ADB = 100/2 = 50 deg.

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