Question

ABCD is a rhombus such that angle ACB=40 degree, then angle ADB=
A)45degree
B)50degree C)40degree
D)60degree ​

Answer 1

Answer:

b) 50 degree

Step-by-step explanation:

rhombus ABCD,

angle ACB=angle CAD=40.

(alternate interior angle )

Now,

angle AOD =90

(diagonals of rhombus bisect each other at 90 degree)

therefore,in triangle AOD,

angle COD +angle AOD+angle ODA=180

40+90+ADB=180

ADB=180-130=50..