Question

. ABCD is a rhombus such that angle ACB = 40o
, find angle DBC.

Answer 1

ACB=40°

x+x+40° =180°

2x +40° =180°

2x=180°-40°

2x=140°

x=140°/2

x= 70°

therefore x+x+40=180°

70+70+40=180°

180°=180°

therefore angle DBC IS =70°