Question

ABCD is a rhombus such that angle ACB=50°. them angle ADB is______​

Answer 1

Answer:

180-50

ANSWER

HOPE IT HELPS

Answer 2

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$\huge{\underline{\underline{\sf{\red{SOLUTION:-}}}}}$

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$\sf{\underline{\green{Answer-}}}$

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• Angle ABD is 40°.

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$\sf{\underline{\green{Given-}}}$

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• ABCD is a rhombus and angle ACB=50°.

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$\sf{\underline{\green{Find-}}}$

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• We have to find value of angle ADB.

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$\sf{\underline{\green{Explanation-}}}$

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$\sf\:As\:we\:know\:ABCD\:is\:a\: rhombus-$

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$\sf\longrightarrow\: AD \: ∥ \: BC \: and \: AC \: are \: transversal$

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$\sf\longrightarrow∠ \: DAC = ∠ \: ACB \: (These \:∠ \: are \: alternate \: angles)$

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$\longrightarrow \: \sf \: Then \: ∠ \: DAC = 50°$

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$\sf\longrightarrow \: As \: we \: know \: sum \: of \: all\: angles \: of \: a \: ∆ \: is \: 180°$

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$\sf\longrightarrow\: In \: ΔAOD \: (By \: using\: property \: of \: amgle \: sum)$

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$\sf\longrightarrow\: ∠ \: AOD \: + \: ∠ \: DAO \: + \: ∠ \: ADO \:= \: 180°$

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$\sf\longrightarrow \: ∠ \: 90° + ∠ \: 50° + ∠ \: ADO = 180°$

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$\sf\longrightarrow \: ∠ \: 140°+ ∠ \: ADO = 180°$

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$\sf\longrightarrow∠ \: ADO = 180°-140°$

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$\sf\longrightarrow∠ \: ADO = 40°$

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$\boxed{\sf\green\longrightarrow{\red{Hence,∠ \: ADB = 40°}}}$

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