Question

Abcd is a rhombus such that angle acb equals to 40 degrees then angle adb is

Answer 1

in rhombus ABCD,

angle ACB = angle CAD = 40. (. alt int. angle )

now,

angle AOD = 90 ( diagonal of rhombus bisect each other at 90 degree)

so, in triangle AOD ,

angle COD + angle AOD +angle ODA = 180

40 + 90 + ADB = 180

ADB = 180 - 130= 50

so, this is your answer

Answer 2

Step-by-step explanation:

50 degree .............