ABCD is a rhombus such that angleACB=40.What will be angleADB
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Answered by
7
in rhombus ABCD,
angle ACB = angle CAD = 40. (. alt int. angle )
now,
angle AOD = 90 ( diagonal of rhombus bisect each other at 90 degree)
so, in triangle AOD ,
angle COD + angle AOD +angle ODA = 180
40 + 90 + ADB = 180
ADB = 180 - 130= 50
so, this is your answer
angle ACB = angle CAD = 40. (. alt int. angle )
now,
angle AOD = 90 ( diagonal of rhombus bisect each other at 90 degree)
so, in triangle AOD ,
angle COD + angle AOD +angle ODA = 180
40 + 90 + ADB = 180
ADB = 180 - 130= 50
so, this is your answer
shivani5767:
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2
the angle ADB is 40 because all angles are equal in rhombus
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