ABCD is a rhombus such that one of its diagonals is equal to its side. Find the angles of rhombus ABCD
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Answer:
if one diagonal is equal to side of rhombus then all sides of rhombus are equal to the one diagonal
the diagonal will divide the rhombus in two equilateral triangles
then
let all equal Side as well as equal diagonal be x
solution
x+x+x=180°(Angle Sum Theorem)
3x=180°
x=180/3
x=60°
we get two Angle of rhombus=60°
then other two Angles are
180-60=120°[the sum of two adjacent Angle is 180°]
Angles of other two Angle are 120°
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