Question

abcd is a rhombus then find the value of x

Answer 1

this is your answer

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Answer 2

Answer:

Concept:

sum property of a triangle

Step-by-step explanation:

Given:

ABCD rhombus

Find:

value of x

Solution:

We know that all the sides are equal in a rhombus

Since, diagonals bisect the angles in rhombus

We have,

$\angle B A D=120^{\circ} and \angle D B C=x \\ \angle B=2 \times \angle D B C=2 x \\ \angle D A B+\angle B=180^{\circ}\left[\right. sum of adjacent angles of rhombus are equal to \left.180^{\circ}\right] \\ \Rightarrow 130^{\circ}+2 x=180^{\circ} \Rightarrow 2 x=180^{\circ}-130^{\circ} \\ \Rightarrow x=\frac{50}{2}=25^{\circ} \\ \angle D A B+\angle B=180^{\circ} [sum of adjacent angles of rhombus are equal to 180^{\circ} ]$

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