ABCD is a rhombus whose diagonal AC makes an angle theta with AB. If cos theta = 3/5 and OB = 4cm, find the side and diagonals of the rhombus.
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draw a rhombus ABCD
draw AC and BD as its diagonals
Now,The intersectiom point is O.
In the triangle ABO angle A=theta
lets its hypotnuse be x and adjacent side be y.
It was given that OB=4cm so OC=4cm because in rhombus diadonals bisect each other.
It was given cos theta=3/5
☆x=5
y=3
☆AO=3
OD=3
all sides are equal in a rhombus
So,AB=BC=CD=DA=5cm.
Hope it helps you.
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Answer :D
draw a rhombus ABCD
draw AC and BD as its diagonals
Now,The intersectiom point is O.
In the triangle ABO angle A=theta
lets its hypotnuse be x and adjacent side be y.
It was given that OB=4cm so OC=4cm because in rhombus diadonals bisect each other.
It was given cos theta=3/5
☆x=5
y=3
☆AO=3
OD=3
all sides are equal in a rhombus
So,AB=BC=CD=DA=5cm.
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