ABCD is a rhombus whose diagonals AC and BO intersect at a point 0. If side AB= 13 cm and the diagonal BO= 10 cm, then find the length of diagonal AC
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According to quesion,
AB=10, BD=16
From figure,
AO+OC=AC
& AO=OC
=> 2AO=AC
In △AOB, from pythagorous
AB
2
=AO
2
+BO
2
=> 100=64+AO
2
=> AO=6
Since, AC=2OA,
Hence, AC=12cm
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