Question

ABCD is a rhombus whose diagonals are 22 cm and 14 cm. A semi circle is drawn with diameter AC as ahown in figure. Find the area of the shaded region.

Answer 1

Answer:

190.14 cm²

Step-by-step explanation:

Area of Δ ACD = Area Δ ABC

⇒ Replace Δ ACD with Δ ABC

⇒ Shaded area will be the area of the semi circle

Find the area:

Area = 1/2 πr²

Area = 1/2 π(22 ÷ 2)²  = 190.14 cm²

Answer: The area of the shaded region is 190.14 cm²

Answer 2

Answer:

190.14 sq. cm

Step-by-step explanation:

The two diagonals of a rhombus are perpendicular; that is, a rhombus is an ortho-diagonal quadrilateral and bisect by equal distance.

therefore, Area of Δ ACD = Area Δ ABC

Area of shaded region is = Area of  Δ ABC +Area of Semi-circle-Area of Δ ACD

=Area of Semi-circle with diagonal 22 cm

Now,

Area of semi-circle = 1/2 πr²

Area = 1/2 π(11)²  = 190.14 cm²

Answer: The area of the shaded region is 190.14 cm²