ABCD is a rhombus. Whose diagonals intersect at E. If
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Answered by
0
Answer:
Given ABCD is a rhombus and diagonals intersect at E
Since in a rhombus diagonals bisect each other
∣
EA
∣=∣
EC
∣ and ∣
EB
∣=∣
ED
∣
but since they are opposite to each other they are of opposite signs
⇒
EA
=−
EC
and
EB
=−
ED
⇒
EA
+
EC
=
O
...(i) and
EB
+
ED
=
O
Add (1) and (2)
⇒
EA
+
EB
+
EC
+
ED
=
O
∴ Answer is option (A)
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