ABCD is a rhombus whose diagonals intersect at E. Then EA + EB + EC+
ED equals
(a) 0 (b) AD
(C) 2BC (d) 2AD
Answers
Answered by
13
Answer:
2 BC
Explanation:
Answered by
8
ANSWER IS C
FRIEND MARK BRAINLIEST
BEACAUSE
WHEN 2 DIAGNOLS FORMS A TRIANGLE
IT BECOMES 2 X DIAGNOLS IE,
2BC
PLS FOLLOW
PLS Mark BRAINLIEST
PLS MATE
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