Math, asked by ritaachhetri2002, 10 months ago

ABCD is a rhombus whose diagonals intersect at E. Then EA + EB + EC+ED equals(a) 0 (b) AD(C) 2BC (d) 2AD

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Answered by Jagritimishra567

1

Answer:

(c) or (d) I think this is right

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