Question

ABCD is a rhombus whose diagonals intersect at o if AB =10 cm diagonal BD=16 cm. then find the length of other diagonal Ac..pls guys make it fast ...i need correct answer

Answer 1

AC and BD intersect each other on the mid point O in 90°.So BO=8cm.And AB=10cm.
From Pithagoras's rule
AO=√(AB^2-BO^2)
=√(100-64)
=√36
=6.
And we know AC=2AO
=2*6=12cm

Answer 2

Answer:

Side of Rhombus are  equal.

AB = BC = CD = DA

∴AC=4×(side)2−(DiagonalBD)2

AC=4×(10)2−(16)2

=400−256

=144

=12cm