ABCD is a rhombus whose diagonals intersect at O.
If AB = 10 cm, diagonal BD = 16 cm, find the length
of diagonal AC.
inmonals
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Answer:
AC and BD intersect each other on the mid point O in 90°.So BO=8cm.And AB=10cm.
From Pithagoras's rule
AO=√(AB^2-BO^2)
=√(100-64)
=√36
=6.
And we know AC=2AO
=2*6=12cm
Step-by-step explanation:
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