Math, asked by bhfury2007, 6 months ago

ABCD is a rhombus whose diagonals intersect at O.
If AB = 10 cm, diagonal BD = 16 cm, find the length
of diagonal AC.
inmonals​

Answers

Answered by handsomeram16645
4

Answer:

AC and BD intersect each other on the mid point O in 90°.So BO=8cm.And AB=10cm.

From Pithagoras's rule

AO=√(AB^2-BO^2)

=√(100-64)

=√36

=6.

And we know AC=2AO

=2*6=12cm

Step-by-step explanation:

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