ABCD is a rhombus whose diagonals intersect at o if AB =10 cm diagonal BD=16 cm. then find the length of other diagonal Ac..pls guys make it fast ...i need correct answer
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The length of AC will be 12 cm.
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AB=10cm
BD=16CM
THEREFORE, OB=8cm( Diagonal bisect each other)
Angle AOB=90°
10^2=8^2+AO^2
OR, 100-64=AO^2
OR, 36=AO^2
OR, AO=6
THEREFORE, DIAGONAL AC=2*6=12CM
BD=16CM
THEREFORE, OB=8cm( Diagonal bisect each other)
Angle AOB=90°
10^2=8^2+AO^2
OR, 100-64=AO^2
OR, 36=AO^2
OR, AO=6
THEREFORE, DIAGONAL AC=2*6=12CM
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