ABCD is a rhombus whose diagonals intersect at O. If AB = 10 cm and diagonal BD = 16 cm .Find the ratio of AC and BD.
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Answer:
Side of Rhombus are equal.
AB = BC = CD = DA
∴AC=√ 4×(side) 2−(DiagonalBD) 2
AC= √4×(10) 2−(16) 2
= √400−256
= √144
=12cm
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