ABCD is a rhombus whose diagonals intersect at O. If AB = 10 cm diagonal BD = 16 cm, then find the length of other diagonal AC
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Step-by-step explanation:
We know in rhombus diagonals bisect each other at right angle.
In ΔAOB
BO = BD/2 = 16/2 = 8cm
Using Pythagoras theorem in ΔAOB
AB2 = AO2 + BO2
102 = AO2+ 82
100-64 = AO2
AO2 = 36
AO = √36 = 6cm
∴ Length of diagonal AC is 6 × 2 = 12cm.
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