Question

ABCD is a rhombus whose diagonals intersect at O. If AB=10 cm, diagonal BD=16 cm, find the length of diagonal AC

Answer 1

#AlexaRousey here!!

Given :
Side of rhombus = 10cm,
Diagonal BD = 16cm

Since side^2 = (d1/2)^2 + (d2/2)^2

=) 10^2 = (16/2)^2 + (d2/2)^2

=) 100 = 64 + (d2/2)^2

=) 100-64 = (d2/2)^2

=) 36 = (d2/2)^2

=) 6 = d2/2

=) 6*2 = d2 = 12cm.

Thanks!!