Question

ABCD is a rhombus whose diagonals intersect at O. if AB is 10 cm and BD is 16 cm find the length of diagonal AC.

Answer 1

Answer:

12

Step-by-step explanation:

AC and BD intersect each other on the mid point O in 90°.So BO=8cm.And AB=10cm.

From Pithagoras's rule

AO=√(AB^2-BO^2)

=√(100-64)

=√36

=6.

And we know AC=2AO

=2*6=12cm