Question

ABCD is a rhombus whose diagonals intersect at O show that triangle AOB ~= triangle COD​

Answer 1

Answer:

Diagonals of rhombus bisect each other.

So, OA = OC and OB = OD [given]

In triangle AOB and triangle COD

AO = OC [ GIVEN ]

∠AOB = ∠COD [ VERTICALLY OPPOSITE ANGLES]

BO = OD [ GIVEN ]

So, Δ AOB ≅ Δ COD [ SAS ]

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Answer 2

Step-by-step explanation:

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