ABCD is a rhombus whose diagonals intersect at O show that triangle Aob is congruent to triangle COD
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SakshiGouniyal:
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Answered by
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consider the attached diagram,
ΔAOB, ΔCOD
AB=CD, ∠AOB = ∠COD
∵AB║CD ∴ ∠ABO = ∠CDO & ∠BAO = ∠DCO
hence ΔAOB & ΔCOD are congruent
ΔAOB, ΔCOD
AB=CD, ∠AOB = ∠COD
∵AB║CD ∴ ∠ABO = ∠CDO & ∠BAO = ∠DCO
hence ΔAOB & ΔCOD are congruent
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